(x-[1-5i])(x+[1-5i])=0

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Solution for (x-[1-5i])(x+[1-5i])=0 equation: 


Simplifying
(x + -1[1 + -5i])(x + [1 + -5i]) = 0
(x + [1 * -1 + -5i * -1])(x + [1 + -5i]) = 0
(x + [-1 + 5i])(x + [1 + -5i]) = 0

Reorder the terms:
(-1 + 5i + x)(x + [1 + -5i]) = 0

Remove brackets around [1 + -5i]
(-1 + 5i + x)(x + 1 + -5i) = 0

Reorder the terms:
(-1 + 5i + x)(1 + -5i + x) = 0

Multiply (-1 + 5i + x) * (1 + -5i + x)
(-1(1 + -5i + x) + 5i * (1 + -5i + x) + x(1 + -5i + x)) = 0
((1 * -1 + -5i * -1 + x * -1) + 5i * (1 + -5i + x) + x(1 + -5i + x)) = 0
((-1 + 5i + -1x) + 5i * (1 + -5i + x) + x(1 + -5i + x)) = 0
(-1 + 5i + -1x + (1 * 5i + -5i * 5i + x * 5i) + x(1 + -5i + x)) = 0

Reorder the terms:
(-1 + 5i + -1x + (5i + 5ix + -25i2) + x(1 + -5i + x)) = 0
(-1 + 5i + -1x + (5i + 5ix + -25i2) + x(1 + -5i + x)) = 0
(-1 + 5i + -1x + 5i + 5ix + -25i2 + (1 * x + -5i * x + x * x)) = 0

Reorder the terms:
(-1 + 5i + -1x + 5i + 5ix + -25i2 + (-5ix + 1x + x2)) = 0
(-1 + 5i + -1x + 5i + 5ix + -25i2 + (-5ix + 1x + x2)) = 0

Reorder the terms:
(-1 + 5i + 5i + 5ix + -5ix + -25i2 + -1x + 1x + x2) = 0

Combine like terms: 5i + 5i = 10i
(-1 + 10i + 5ix + -5ix + -25i2 + -1x + 1x + x2) = 0

Combine like terms: 5ix + -5ix = 0
(-1 + 10i + 0 + -25i2 + -1x + 1x + x2) = 0
(-1 + 10i + -25i2 + -1x + 1x + x2) = 0

Combine like terms: -1x + 1x = 0
(-1 + 10i + -25i2 + 0 + x2) = 0
(-1 + 10i + -25i2 + x2) = 0

Solving
-1 + 10i + -25i2 + x2 = 0

Solving for variable 'i'.

The solution to this equation could not be determined.

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